Răspuns: [tex]\bf \red{\underline{~1~}}[/tex]
Explicație pas cu pas:
[tex]\bf \big(16\cdot12^{10}-4 \cdot 12^{10} \big):12^{11}=[/tex]
[tex]\bf 12^{10}\cdot \big(16\cdot12^{10-10}-4 \cdot 12^{10-10} \big):12^{11}=[/tex]
[tex]\bf 12^{10}\cdot \big(16\cdot12^{0}-4 \cdot 12^{0} \big):12^{11}=[/tex]
[tex]\bf 12^{10}\cdot \big(16\cdot1-4 \cdot 1 \big):12^{11}=[/tex]
[tex]\bf 12^{10}\cdot \big(16-4 \big):12^{11}=[/tex]
[tex]\bf 12^{10}\cdot12:12^{11}=12^{10+1}:12^{11}=[/tex]
[tex]\bf 12^{11}:12^{11}=12^{11-11}=12^{0}=\red{\underline{~1~}}[/tex]
[tex]==pav38==[/tex]
