Va rog am nevoie de acest exercitiu neapărat ​

Răspuns:

a)

[tex] {2}^{15} + 2 \times {4}^{7} = {2}^{15} + {2}^{15} = {2}^{16} [/tex]

[tex] {2}^{16} = ( {2}^{2} )^{8} = {4}^{8} = > {5}^{8} > {2}^{16} [/tex]

b)

[tex] {5}^{14} = ( {5}^{2} )^{7} = {25}^{7} [/tex]

[tex] {3}^{21} = ( {3}^{3} )^{7} = {27}^{7} = > {5}^{14} < {3}^{21} [/tex]