Răspuns:
a) (5¹⁷ × 5¹⁸ + 7²³ ÷ 7¹⁵) ÷ (7 × 7² × 7⁵ + 5⁵⁰ ÷ 5¹⁵)
[tex]( {5}^{17 + 18} + {7}^{23 - 15}) \div ( {7}^{1} \times {7}^{2} \times {7}^{5} + {5}^{50} \div {5}^{15} ) \\ ( {5}^{35} + {7}^{8} ) \div ( {7}^{1 + 2 + 5} + 5 {}^{50 - 15} ) \\ (5 {}^{35} + {7}^{8} ) \div (7 {}^{8} + 5 {}^{35} ) \\ \frac{5 {}^{35} + 7 {}^{8} }{7 {}^{8} + 5 {}^{35} } = 1[/tex]
Se taie 5³⁵ de sus cu 5³⁵ de jos, la fel, se taie 7⁸ de sus cu 7⁸ de jos.
