2. Rezolvati in multimea numerelor naturale ecuatiile: a) (x-4):5 +50 = 200; b) 125 (x+3)+ 25 = 1025; c) (2x+11):3-4=3

Răspuns :

a) (x-4):5+50=200
(x-4):5=200-50=150
(x-4)=150:5
x-4=30
x=30+4
x=34

b) 125(x+3)+25=1025
125(x+3)=1025-25=1000
x+3= 1000:125=8
x=8-3
x=5

c) (2x+11):3-4=3
(2x+11):3=3+4=7
2x+11= 7 x 3=21
2x=21-11=10
x=10:2
x=5

Coroana thanks