a) x+12=25 b)x+1,3=2,45
x=25-12 x=2,45-1,3
x=13 x=1,15
[tex]x + \frac{1}{4} = \frac{4}{3} \\ x = \frac{4}{3} - \frac{1}{4} \\ amplifici \ cu \ 4 \ prima \ si \ cu \ 3 \ la \ a \ doua \\ x = \frac{16}{12} - \frac{3}{12} \\ x = \frac{13}{12} [/tex]
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