Răspuns: [tex]\bf \red{\underline{x = 7}}[/tex]
Explicație pas cu pas:
Buna !
[tex]\bf 2\cdot 8^{5x-6}=4^{44}[/tex]
[tex]\bf 2^{1}\cdot \Big(2^{3} \Big)^{(5x-6)}=\Big(2^{2}\Big)^{44}[/tex]
[tex]\bf 2^{1}\cdot 2^{3\cdot(5x-6)}=2^{2\cdot 44}[/tex]
[tex]\bf 2^{1}\cdot 2^{15x-18}=2^{88}[/tex]
[tex]\bf 2^{1+15x-18}=2^{88}[/tex]
[tex]\bf 2^{15x-17}=2^{88}\implies 15x-17=88[/tex]
[tex]\bf 15x=88+17[/tex]
[tex]\bf 15x=105 ~~~\bigg|:15[/tex]
[tex]\bf \red{\underline{x = 7}}[/tex]
Bafta multa !