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Răspuns: 1 ✅

[tex] \bf \: a = 100 - ( {7}^{2} + {3}^{3} )[/tex]

[tex] \bf \: a = 100 - (49 + 27)[/tex]

[tex] \bf \: a = 100 - 76[/tex]

[tex] \boxed{\boxed{ \bf{a = 24}}}[/tex]

[tex] \bf \: b = 25 {}^{4} \div {5}^{8} [/tex]

[tex] \bf \: b = {5}^{2 \times 4} \div 5 {}^{8} [/tex]

[tex] \bf \: b = {5}^{8} \div {5}^{8} [/tex]

[tex] \boxed{ \boxed {\bf \: b = 1}}[/tex]

✏ [tex] \bf \pink{b {}^{a} = {1}^{24} = > \boxed{ \bf \: {b}^{a} = 1} }[/tex] ☑

6. Știind că:

a = 100 - (7² + 3³)

a = 100 - (49 + 3³)

a = 100 - (49 + 27)

a = 100 - 76

a = 24

b = 25⁴ : 5⁸

b = (5²)⁴ : 5⁸

b = 5⁸ : 5⁸

b = 1

b^a => 1²⁴ = 1