Salut!
1/[ n × (n + 1)] = 1/n - 1/(n + 1)
x = V1/94 × [(1/1 - 1/2 + 1/2 - 1/3 + ... + 1/24 - 1/25) - ( 1/25 - 1/26 + 1/26 - 1/27 + ... + 1/49 - 1/50 )]}
Se reduc cele cu semn opus.
x = V{1/94 × [(⁵⁰) 1/1 - ²) 1/25) - (²) 1/25 - 1/50)]}
x = V[1/94 × (48/50 - 1/50)]
x = V(1/94 × 47/50)
x = V(1/2 × 1/50) = V(1/100) = V1/V100 = 1/10 € Q