Ex 2.
Metoda I (Metoda reducerii):
{x-3y=5 / *(-2)
{2x+5y=8
{-2x+6y=-10
{2x+5y=8
-----------------
\ 11y=-2
y=[tex]-\frac{2}{11}[/tex]
x=5+3y
x=5-[tex]\frac{3*2}{11} = 5-\frac{6}{11}=\frac{55-6}{11}=\frac{49}{11}[/tex]
x=[tex]\frac{49}{11}[/tex]
Metoda II (Metoda substitutiei):
{x-3y=5 => x=5+3y
{2x+5y=8=> 2(5+3y)+5y=8
10+6y+5y=8
11y=8-10
11y=-2
y=[tex]-\frac{2}{11}[/tex]
x=5-[tex]\frac{3*2}{11} = 5-\frac{6}{11}=\frac{55-6}{11}=\frac{49}{11}[/tex]
x=[tex]\frac{49}{11}[/tex]
Ex 3.
Notam cu "a" numarul
a+[tex]\frac{a}{2}[/tex]=90
2a+a=180
3a=180
a=60
Raspuns:Numarul este "60"